5.8 Object Equality and Hashing
By default, objects that are instances of different classes or that are instances of a non-transparent class are equal? only if they are eq?. Like transparent structures, two objects that are instances of the same transparent class (i.e., every superclass of the class has #f as its inspector) are equal? when their field values are equal?.
To customize the way that a class instance is compared to other instances by equal?, implement the equal<%> interface.
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equal-to? —
Takes two arguments. The first argument is an object that is an instance of the same class (or a subclass that does not re-declare its implementation of equal<%>) and that is being compared to the target object. The second argument is an equal?-like procedure of two arguments that should be used for recursive equality testing. The result should be a true value if the object and the first argument of the method are equal, #f otherwise. equal-hash-code-of —
Takes one argument, which is a procedure of one argument that should be used for recursive hash-code computation. The result should be an exact integer representing the target object’s hash code. equal-secondary-hash-code-of —
Takes one argument, which is a procedure of one argument that should be used for recursive hash-code computation. The result should be an exact integer representing the target object’s secondary hash code.